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48 lines
1.6 KiB
48 lines
1.6 KiB
6 years ago
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from __future__ import unicode_literals
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from prompt_toolkit.validation import Validator, ValidationError
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__all__ = (
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'PythonValidator',
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)
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class PythonValidator(Validator):
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"""
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Validation of Python input.
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:param get_compiler_flags: Callable that returns the currently
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active compiler flags.
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"""
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def __init__(self, get_compiler_flags=None):
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self.get_compiler_flags = get_compiler_flags
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def validate(self, document):
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"""
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Check input for Python syntax errors.
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"""
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# When the input starts with Ctrl-Z, always accept. This means EOF in a
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# Python REPL.
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if document.text.startswith('\x1a'):
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return
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try:
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if self.get_compiler_flags:
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flags = self.get_compiler_flags()
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else:
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flags = 0
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compile(document.text, '<input>', 'exec', flags=flags, dont_inherit=True)
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except SyntaxError as e:
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# Note, the 'or 1' for offset is required because Python 2.7
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# gives `None` as offset in case of '4=4' as input. (Looks like
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# fixed in Python 3.)
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index = document.translate_row_col_to_index(e.lineno - 1, (e.offset or 1) - 1)
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raise ValidationError(index, 'Syntax Error')
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except TypeError as e:
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# e.g. "compile() expected string without null bytes"
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raise ValidationError(0, str(e))
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except ValueError as e:
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# In Python 2, compiling "\x9" (an invalid escape sequence) raises
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# ValueError instead of SyntaxError.
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raise ValidationError(0, 'Syntax Error: %s' % e)
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